Factoring Calculator - How to Factor an Algebraic Equation?

Factoring calculator is an essential technique to simply most of the algebraic equation that helps to find out the real value of a variable. The algebra is one of the important parts of mathematics and most of the students scared to solve an algebraic equation and find out their factors. Actually, students need to use various mathematical operations such as addition, multiplication, division and subtractions two. On the other hand, keeping essential formulas to solve the given equation is also frustrating for students. Thus, you have the option to choose the factor calculator that can help you to solve any of the algebraic equation.

Consider some examples to find out their factors as

(x + 3) (x – 3)

x² + 2x – 3 = 0

x³ + 3x² + 12x + 12 = 0

These are some examples of an algebraic equation that required huge attention while finding their factors. It is quite easy to find out factors of any numbers but difficult when you are going to find factors of an algebraic equation.

To find factors for linear equation consider several examples as-

1.    2x + 5 = 0

2.    2x + 4x – 12 = 48

3.    13x / 2 = 39

These are some linear equation whose factors you are finding. It is quite easy to find factors of linear equation. First transfer the number opposite to the variable element. If there are more than two variables, then try to add them and transfer remaining part in different side. You need to eliminate the coefficient term to find the factors of any linear equation. Read the content below in the article to know the solution-

For first equation: 2x + 5 = 0

2x = -5

X = -5/2

For second equation

2x + 4x – 12 = 48

6x – 12 = 48

6x = 60

x = 10

Now, the factor is 10

For third equation

13x / 2 = 39

x = 3 * 2

x = 6

Though, it is simple to find out factors for a linear equation. On the other hand, you feel difficulties while solving higher order algebra equations. Consider a quadratic equation to find out factors by factoring calculator. Quadratic equation can be solved by the particular formula as-

Put the values of a, b, and c to find out the factors of given algebraic or quadratic equation. For better understanding consider a quadratic equation as

x² + 5x +10 = 0

Now, put the values of number, coefficient, and coefficient of now, you will get the figure as

By solving above figure, you can get two values for X. The major concern is that the student needs to perform various mathematical operations which are difficult to solve. Thus, you can find factoring calculator to find the factors of given equation. Here you do need to enter a question on the required field then you will get the right solution of any algebraic equation. Whether the equation is linear, quadratic or higher order degree, you can find its factors within seconds. You will get the explained solution or the short answer.

·         Benefits of factoring calculator to solve algebraic equation

·         No need to perform various mathematical operations

·         Use digital algebraic calculator to find out factors

·         Get answer in short and expanded form

·         The factoring calculator is best to get factors in few seconds

These are some benefits of using the factoring calculator to find out factors of any algebraic equation.

Equation Solver – A Guide to Solve Equations One by One

Equations seem to be a tough mathematics concept for many students, but it is not. Once you understand the right and proper concept to solve the equation, it becomes an interesting topic for you. Today, we are going to see certain techniques via which one can easily solve a linear equation. So, let’s start it: 

Solving equations

Equations consist of variables and constant terms. We have to find the value of given variable for example x. Let’s understand it with an example: 3 + x = 7

 In the given equation, we need to solve for X.  To solving this simple equation, we need to arrange the “Like terms” on both the sides, i.e., L.H.S and R.H.S.  After the arrangement of like terms, we get 4 as an answer:

3 + x = 7

x = 7 – 3

x = 4

There is only one variable, i.e., X in the equation and we have got two numbers. So, we have to arrange the numbers on one side. While changing the sides of constants and variable terms, make sure to change their signs as well. In the above example, x remains on L.H.S. However, we have shifted 3 on the R.H.S. After coming on the R.H.S, its sign becomes negative to positive and same goes with the variables also.

1.  Solving equation (using subtraction & addition properties)

 We have equation 3x + 3 = x +15, let’s start solving it:

3x + 3 = x +15

3x - x = 15 - 3

(In this step, we have arranged “like terms,” and thus terms with variables shifted on L.H.S and constant terms on the R.H.S.)

2x = 12

(After solving them, we have got 2x and 12.)

x = 6

After further multiplications, we have got answer 6 which is the right value of X.  Is it simple right? So, no let’s move on to the multiplication method.

2. Solving equation (Using multiplication property)

We solve equation 

plus going to discuss some important point’s one need to consider while using multiplication property.

I am going to explain it in a very simple way. In this method, we use multiply both the sides by using a nonzero quantity to get the answer. Let’s see how to do it? 

(In this step, we have canceled 4 as the numerator gets canceled by the denominator because of being a multiple of 4.  However, on the R.H.S we need to multiply 4 from 3 which results in 12.  Yes, you can direct multiple 4 from 3 but do this only when you understand the concept properly.

x = 12

When we solve for x, we got to answer 12.  The method is very easy, however; make sure to practice it more often for perfection.

3. Solving equation (using division property)

Let’s take an example 4x = 12. Now, in this one, we are going to divide the terms by a nonzero quantity to get the answer.

(In the above step, we have divided both the sides by 4 and thus got 3 as the value of x. talking about the L.S.H then 4 in denominator and numerator got canceled. On R.H.S, number 12 is divided by 4, and we got to answer 3. 

The above three concepts are easy to practice, so go for the concepts and improve your linear equation solving skills.